2(x^2+7x)=9x

Solution for 2(x^2+7x)=9x equation:

2(x^2+7x)=9x

We move all terms to the left:

2(x^2+7x)-(9x)=0

We add all the numbers together, and all the variables

-9x+2(x^2+7x)=0

We multiply parentheses

2x^2-9x+14x=0

We add all the numbers together, and all the variables

2x^2+5x=0

a = 2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*2}=\frac{-10}{4}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*2}=\frac{0}{4}
=0
$